The number of values of x in the interval [0,5π] satisfying the equation 3sin2x−7sinx+2=0 is
A
0
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B
5
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C
6
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D
10
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Solution
The correct option is C6 Given quadratic equation 3sin2x−7sinx+2=0 ⇒(3sinx−1)(sinx−2)=0 sinx=13,2 But, sinx≠2 So, sinx=13 In the interval [0, 5π] there are 6 solutions .