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Question

The number of values of x in the interval [0,5π] satisfying the equation 3sin2x7sinx+2=0 is

A
5
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B
6
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C
10
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Solution

The correct option is B 6

3sin2x7sinx+2=0
or (sinx2)(3sinx1)=0
sinx=13=sinα (say)(sinx=2 is not possible)
There exists two values in(0,π),(2π,3π) and (4π,5π).
Hence there are six solutions


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