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Question

The number of values of x satisfying the equation 1+x=sgn(x) is
(where sgn(x) denotes the signum function)

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Solution

sgn(x)=1,x<00,x=01,x>0

Now,
If x>0,1+x=1x=0 (rejected)
If x=0,1+x=0x=1 (rejected)
If x<0,1+x=1x=2

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