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Question

The number of values of x satisfying the equation 3 sin2x7 sinx+2=0 in the intarval [0,5π].

A
0
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B
5
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C
6
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D
10
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Solution

The correct option is D 6
Given quadratic equation is 3sin2x7sinx+2=0

sinx=7±49246=7±56=13,2

Since sinx<1 , the possible value of sinx is 13

In the interval [0,π] , the number of solutions is 2.

In the interval [π,2π] , the number of solutions is 0.

Therefore in interval [0,5π] , the number of solutions is 2+0+2+0+2=6

Therefore option C is correct.

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