The number of vectors of unit length perpendicular to the vectors a=2i+j+2k
and b=j+k is

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Solution

The answer is 2. One in the direction of the cross product of both the vectors and the other in the opposite direction!

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Similar questions

\vec{a} = 2 \hat{i} + \hat{j} + 2 \hat{k} and \vec{b} = \hat{j} + \hat{k}

\vec{a} = 2 \hat{i} + \hat{j} + 2 \hat{k} and \vec{b} = \hat{j} + \hat{k} is

4 \hat{i} - \hat{j} + 3 \hat{k} and - 2 \hat{i} + \hat{j} - 2 \hat{k} .

\vec{a} = 2 \hat{i} + \hat{j} + \hat{k} and \vec{b} = \hat{i} + 2 \hat{j} + \hat{k} .

\to a =^i +^j

\to b =^j +^k

\sqrt{2}

3 i - j - k

i + j - 2 k

2 i + 2 j + k

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