The number of water molecules acting as ligands in $C u S O_{4} .5 H_{2} O, Z n S O_{4} .5 H_{2} O, F e S O_{4} .7 H_{2} O$ respectively are:

5, 5, 7

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4, 5, 4

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4, 4, 6

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4, 4, 7

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Solution

The correct option is C $4, 4, 6$
The coordination number of $C u^{2 +}, Z n^{2 +}$ and $F e^{2 +}$ are $4, 4$ and $6$ respectively.
The complexes are:
$[C u (H_{2} O)_{4}] S O_{4} . H_{2} O$
$[Z n (H_{2} O)_{4}] S O_{4} . H_{2} O$
$[F e (H_{2} O)_{6}] S O_{4} . H_{2} O$

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Similar questions

C u S O_{4} .5 H_{2} O, Z n S O_{4} .5 H_{2} O, F e S O_{4} .7 H_{2} O

{C u}^{2 +}

C u S O_{4} \cdot 5 H_{2} O

C u S O_{4} .5 H_{2} O

1 \times 10^{22}

C u S O_{4} \cdot 5 H_{2} O

1 \times 10^{22}

C u S O_{4} \cdot 5 H_{2} O

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