Question

The number of water molecules in 250 $mL$ of water is closest to
Given
$Densityofwateris1.0gm{L}^{–1};Avogadr{o}^{\prime }snumber=6.023\times {10}^{23}$

• A. $83.6\times {10}^{23}$
• B. $13.9\times {10}^{23}$
• C. $1.5\times {10}^{23}$
• D. $33.6\times {10}^{23}$

Answer 1

The correct option is A $83.6\times {10}^{23}$

$Densityofwater=1g/mLSo250mL=250gwaterMolesof{H}_{2}O=\frac{250}{18}Numberofwatermolecules=\frac{250}{18}\times 6.023\times {10}^{23}=83.6\times {10}^{23}$