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Byju's Answer
Standard XII
Chemistry
Uses of Calcium Sulphate
The number of...
Question
The number of water molecules in one molecule of gypsum, dead burnt plaster and plaster of paris, respectively
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Solution
The chemical formulae of the given compounds are:
(i) Gypsum
C
a
S
O
4
.2
H
2
O
(ii) Dead burnt plaster
C
a
S
O
4
(iii) Plaster of Paris
C
a
S
O
4
.
1
2
H
2
O
∴
The number of water molecules in gypsum, dead burnt plaster and plaster of Paris are respectively,
2
,
0
and
0.5
.
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Similar questions
Q.
The number of water molecules in gypsum, dead burnt plaster and plaster of paris, respectively
Q.
The sum of the number of water molecules in gypsum and plaster of paris is:
Q.
The difference in number of crystalline water molecules in a molecule of gypsum and a molecule of plaster of Paris is
Q.
The difference in number of water molecules in gypsum and plaster of paris is
Q.
Chemically, Plaster of Paris is calcium sulphate hemihydrate, i.e. containing half molecule of water of crystallisation. It is represented by the formula,
CaSO
4
.
1
2
H
2
O
. Half molecule of water of crystallisation means that one water molecule is shared by two formula units of
C
a
S
O
4
. Hence we also represent its formula as
(
C
a
S
O
4
)
2
.
H
2
O
. The name, Plaster of Paris, was given to this compound because for the first time, it was made from gypsum which was mainly found in Paris. Gypsum has the chemical formula,
C
a
S
O
4
.2
H
2
O
. When plaster of Paris is mixed with water it sets into a hard mass.
(a) The number of water molecules present as water of crsytallisation in gypsum and Plaster of Paris respectively, is
(i)
2
;
1
/
2
(ii)
2
;
5
/
2
(iii)
1
/
2
;
2
(iv)
3
/
2
;
1
/
2
(b) Write the chemical equation for the reaction between plaster of Paris and water.
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