The number of water molecules present in a drop of water (Volume 0.0018 ml) at room temperature is
The correct option is A 6.023×1019
As we know, density is equal to mass upon volume.
We know density of water = 1 gml−1. Hence for water 1 g = 1 ml and 0.0018 ml = 0.0018 g.
Number of moles =WeightMolecular weight
=0.001818
=1×10−4 mol
∴ No. of water molecules = Moles ×NA=6.023×1023×1×10−4
=6.023×1019 molecules.