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Question

The number of water molecules present in a drop of water (Volume 0.0018 ml) at room temperature is

A
6.023×1019
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B
1.084×1018
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C
4.84×1017
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D
5.023×1023
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Solution

The correct option is A 6.023×1019
We know density of water = 1 gml1. Hence for water 1 g = 1 ml and 0.0018 ml = 0.0018 g.
Number of moles =WeightMolecular weight
=0.001818
=1×104 mol
No. of water molecules = Moles ×NA=6.023×1023×1×104
=6.023×1019 molecules.

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