The number of water molecules present in a drop of water (Volume 0.0018ml) at room temperature is
A
6.023×1019
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B
1.084×1018
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C
4.84×1017
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D
5.023×1023
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Solution
The correct option is A6.023×1019 We know density of water = 1gml−1. Hence for water 1 g = 1 ml and 0.0018 ml = 0.0018 g.
Number of moles =WeightMolecular weight =0.001818 =1×10−4mol ∴ No. of water molecules = Moles ×NA=6.023×1023×1×10−4 =6.023×1019 molecules.