The number of waves in the fourth Bohr orbit of hydrogen is

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Solution

The correct option is B
4

b. Number of waves = $\frac{C i r c u m f e r e n c e}{W a v e l e n g t h}$

$\frac{2 π r}{λ}$ = $\frac{2 π r}{\frac{h}{m v}}$ = $\frac{2 π}{h} (m v r)$ = $\frac{2 π}{h} \times \frac{n h}{2 π} = \frac{2 π}{h} \times \frac{4 h}{2 π}$

$∴$ $n$ = $4$

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