Question

The number of waves made by a Bohr electron in an orbit of maximum magnetic quantum number $3$ is:

• A. $3$
• B. $4$
• C. $2$
• D. $1$

Answer 1

Answer: (B)

$4$

Negative quantum number has values from $-l$ to $+l$

$\therefore l=3$

Now, $l$ has value from $0$ to $n-1$,

$\therefore 3=n-1$

$n=4$

No. of waves made by Bohr electron $=n=4$

So, the correct option is $B$