Question

The number of ways in which $12$ different books can be put in three shelves with four on each shelf is

• A. $\frac{12!}{(4!{)}^3}$
• B. $\frac{12!}{(3!)(4!{)}^3}$
• C. $\frac{12!}{(3!{)}^{3}4!}$
• D. none of these

Answer 1

The correct option is A $\frac{12!}{(4!{)}^3}$

Since the shelves which are to receive the books are different, therefore the required number of ways is $=\frac{12!}{(4!{)}^3.}$