Question

The number of ways in which $12$ persons can be divided into three equal group is

• A. $\frac{12!}{(4!{)}^3}$
• B. $\frac{12!}{(3!{)}^4}$
• C. $\frac{12!}{3!(4!{)}^3}$
• D. $\frac{12!}{(4!{)}^5}$

Answer 1

Answer: (A)

$\frac{12!}{(4!{)}^3}$

No. of ways $\frac{12!}{4!4!4!}=\frac{12!}{(4!{)}^3}$