The number of ways in which $20$ persons can sit on $8$ chair round a circular table is:

^{20} P_{8}

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^{19} P_{8}

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\frac{1}{8} .^{20} P_{8}

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Solution

The correct option is B $^{20} P_{8}$
$S e l e c t 8 p e r s o n f r o m 20 p e r s o n =^{20} C_{8} N o w t h e s e 8 p e r s o n c a n b e a r r a n g e d i n = (8 - 1)! = 7! w a y s T o t a l p e r m u t a t i o n =^{20} C_{8} \cdot 7! = (\frac{20! \cdot 7!}{12! \cdot 8!}) = (\frac{1}{8})^{20} P_{8}$

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