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Permutation: n Different Things Taken r at a Time

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Question

The number of ways in which 39312 can be resolved into two factors which are prime to each other is 8.If true enter 1 else 0.

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Solution

$39312 = 2^{4} \times 3^{3} \times 7 \times 13$
There are four distinct primes in factorization of the given number. The required number of ways $2^{3} = 8$

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Permutation: n Different Things Taken r at a Time

Standard XII Mathematics

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