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Question
The number of ways in which 4032 can be resolved as the product of two factors is
The number of ways in which 4032 can be resolved as the product of two factors is
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Solution
The correct option is D 21
No. of factors of 4032 = 7 x 2 x 3 = 42.
Since 4032 is not a perfect square, it can be written as a product of two distinct numbers 21 times.
The pairs of numbers will be - (1,4032), (2,2016), (3,1344), (4,1008), (6,672), (7,576), (8,504), (9,447), (12,336), (14,288), (16,252), (18,224), (21,194), (24,168), (28,144), (32,126), (36,112), (42,96), (48,84), (56,72), (63,64).
21
No. of factors of 4032 = 7 x 2 x 3 = 42.
Since 4032 is not a perfect square, it can be written as a product of two distinct numbers 21 times.
The pairs of numbers will be - (1,4032), (2,2016), (3,1344), (4,1008), (6,672), (7,576), (8,504), (9,447), (12,336), (14,288), (16,252), (18,224), (21,194), (24,168), (28,144), (32,126), (36,112), (42,96), (48,84), (56,72), (63,64).
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