Question

The number of ways in which 5 boys and 4 girls to sit around a table so that all the boys sit together is:

• A. $576$
• B. $720$
• C. $2880$
• D. $1440$

Answer 1

The correct option is C $2880$

As all boys are to sit together, they can be considered as a single element.
$\therefore$Total $no$ of elements $=4+1=5$
$no$ of ways of arranging 5 things in a circle is $(n-1)!=(5-1)!=4!$
$no$ of ways of arranging 5 boys is $5!=120$
$\therefore$Total $no$ of ways $=5!\times 4!=2880$