wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of ways in which 5 boys and 5 girls can be arranged in a row so that no two girls and no two boys are together is

A
2(5!)2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(5!)2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5!6!
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10!
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2(5!)2
There are two ways of doing this

Case I:1st person is a boy.

B1G1B2G2B3G3B4G4B5G5–––––––––––––––––––––––––––

The no. of ways in which the boys can be rearranged among themselves is 5!. The same is for the girls.
So, the total number of ways
=5!×5!

Case II:1st person in the row is a girl.

G1B1G2B2G3B3G4B4G5B5–––––––––––––––––––––––––––

Same as above, 5!×5!
So, the total no. of ways is =2×(5!)×(5!)
So, total number of ways =2×(5!)2

Hence, option A is correct.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Permutations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon