Question

The number of ways in which $5$ girls and $2$ boys can sit in row such that the boys are not together.

• A. $3600$
• B. $7200$
• C. $1800$
• D. $3660$

Answer 1

The correct option is A $3600$

The arrangement can be like
$\_G\_G\_G\_G\_G\_$
The number of ways in which girls can seat is $5!=120$
The number of ways in which boys can seat is ${}^6{P}_2=30$
So, total number of ways=$3600$