The number of ways in which $5$ male and $2$ female members of committee can be seated around a table, so that two female members are not seated together is

480

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600

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720

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840

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Solution

The correct option is B $600$
Total no of ways when there is no restriction $= (7 - 1)! = 6! = 720.$
When two females are seated together,
$\Rightarrow$ No of ways $= (6 - 1)!$
$= 5!$
$= 120.$
$\Rightarrow$ So total no. of ways $= 720 - 120$
$= 600.$
hence, the answer is $600.$

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The number of ways in which 5 male and 2 female members of committee can be seated around a table, so that two female members are not seated together is

The correct option is B 600Total no of ways when there is no restriction =(7−1)!=6!=720.When two females are seated together,⇒ No of ways =(6−1)! =5! =120.⇒ So total no. of ways =720−120 =600.hence, the answer is 600.

The number of ways in which $5$ male and $2$ female members of committee can be seated around a table, so that two female members are not seated together is

The correct option is B $600$
Total no of ways when there is no restriction $= (7 - 1)! = 6! = 720.$
When two females are seated together,
$\Rightarrow$ No of ways $= (6 - 1)!$
$= 5!$
$= 120.$
$\Rightarrow$ So total no. of ways $= 720 - 120$
$= 600.$
hence, the answer is $600.$