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Question

The number of ways in which 5X′s can be placed in the square of the figure so that no row remains empty:
1080618_87949d1e985f4bff84da78d2574db1b3.png

A
97
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B
44
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C
100
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D
126
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Solution

The correct option is A 44
Case (1):
let number of Xs in first row be 3,second row be 1,third row be 1

no of ways for this is 4C3×2C1×2C1=16

Case (2):

let number of Xs in first row be 2,second row be 1 or 2,third row be 2 or 1 respectively

no of ways for this is 2(4C2×2C1×2C1)=24

Case (3):

let number of Xs in first row be 1,second row be 2,third row be 2

no of ways for this is 4C1×2C2×2C2=4

Total number of ways is 16+24+4=44

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