Question

The number of ways in which 7 men can sit in a round table so that every person shall not have the same neighbours in any two arrangements is

• A. 360
• B. 720
• C. 700
• D. 300

Answer 1

The correct option is A 360

7 men can be sit at a round table in $(7-1)!=6!$ ways. Since there is no distinction between clockwise and anticlockwise arrangements, the required number of arrangements is $\frac{6!}{2}$

$=\frac{720}{2}=360$

Hence the answer is A.