Question

The number of ways in which 8 boys can be seated at a round table so that two particular boys are next to each other is

• A. 8! 2!
• B. 7! 2!
• C. 6! 2!
• D. 6!

Answer 1

Answer: (C)

6! 2!

Here total number of boys is 8 and two have to seat adjacent to one another, so consider these two as a one and arrange them in $2!$ ways, So total number dissimilar item is 7, and these can be arrange in round table in $(7-1)!=6!$ ways.
Hence total number of ways is $=6!\cdot 2!$