Question

The number of ways in which 8 red roses and 5 white roses of different sizes can be made out to form a garland so that no two white roses come together is

• A. $\frac{8!}{2}.{}^8{P}_5$
• B. $\frac{7!}{2}.{}^8{P}_5$
• C. $\frac{7!}{2}.{}^9{P}_5$
• D. $7!{}^4{P}_3$

Answer 1

The correct option is B $\frac{7!}{2}.{}^8{P}_5$

$\frac{7!}{2!}.{}^8{P}_5$