Question

The number of ways in which a mixed double tennis game can be arranged from amongst $9$ married couple if no husband & wife plays in the same game is?

• A. $756$
• B. $3024$
• C. $1512$
• D. $6048$

Answer 1

Answer: (C)

$1512$

2 gents can be selected from 9 gents in ${}^9{C}_2$ ways

2 ladies can be selected from $9-2=7$ ladies

in ${}^7{C}_{2}ways$

$\therefore$ The number of required ways ${=}^9{C}_2{\times }^7{C}_2\times 2$

$=1512ways$