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Question
The number of ways in which five students of different heights can sit in a row so that the tallest and the shortest may not sit together is
The number of ways in which five students of different heights can sit in a row so that the tallest and the shortest may not sit together is
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Solution
The correct option is C 72
Required arrangements = Total number of arrangements – The number of arrangements in which they sit together = 5! – 4!2! = 4! (5 – 2) =24×3=72
Required arrangements = Total number of arrangements – The number of arrangements in which they sit together = 5! – 4!2! = 4! (5 – 2) =24×3=72
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