1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# The number of ways in which n distinct objects can be put into two different boxes so that no box remains empty is

A
2n1
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
n21
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
2n2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
n22
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is C 2n−2Each object can be put either in box B1 (say) or in box B2(say). So, there are two choices for each of the n objects. Therefore the number of choices for n distinct objects is 2×2×⋯n−times×2=2n One of these choices corresponds to either the first or the second box being empty. Thus, there are 2n−2 ways in which neither box is empty.

Suggest Corrections
9
Join BYJU'S Learning Program
Related Videos
Different to Different
QUANTITATIVE APTITUDE
Watch in App
Join BYJU'S Learning Program