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Standard XII

Mathematics

Combination of n Different Things Taken One or More at a Time

The number of...

Question

The number of ways in which one or more balls can be selected out of $10$ alike white, $9$ alike green and $7$ alike black balls is

892

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881

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891

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879

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Solution

The correct option is D $879$
Required number of ways
$= (10 + 1) (9 + 1) (7 + 1) - 1 = 880 - 1 = 879$

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Combination of n Different Things Taken One or More at a Time

Standard XII Mathematics

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The number of ways in which one or more balls can be selected out of 10 alike white, 9 alike green and 7 alike black balls is

The correct option is D 879Required number of ways =(10+1)(9+1)(7+1)−1=880−1=879

The number of ways in which one or more balls can be selected out of $10$ alike white, $9$ alike green and $7$ alike black balls is

The correct option is D $879$
Required number of ways
$= (10 + 1) (9 + 1) (7 + 1) - 1 = 880 - 1 = 879$