Question

The number of ways in which the letters of the word "HEXAGON" be arranged so that the consonants may always occupy the odd places is

• A. $24$
• B. $144$
• C. $360$
• D. $720$

Answer 1

Answer: (B)

$144$

HEXAGON
Vowels$=A,E,O$
Cons0tants$=G,H,N,X$
$\to$ So, there is only one way in which the consonants occupy the odd places i.e. $1^{st},3^{rd},5^{th}and{7}^{th}$
$\to$ Since there is only one case the total no. of ways$=4!\times 3!$
$=24\times 6$
$=144$