Question

The number of ways of arranging $6$ players to throw the cricket ball so that the oldest player may not throw first is:

• A. $120$
• B. $600$
• C. $720$
• D. $7156$

Answer 1

Answer: (B)

$600$

There is only one player who can be the $Oldest$

The total number of arrangements of $6$ players will be $6!=720$

If the oldest player throws first, then the total arrangements of $5$ members will be $5!=120$

The number of ways of arrangements so that oldest player may not throw first will be $720-120=600$