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Question

The number of ways of distributing 8 identical balls in 3 distinct boxes so that none of the boxes is empty is

A
8C3
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B
21
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C
38
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D
5
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Solution

The correct option is A 21
The number of ways of distributing 8 identical balls in 3 distinct boxes so that none of the boxes is empty is
(81)C(31) [ Using direct formula]
= 7C2
=7×62!
=7×3
=21.

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