1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Fundamental Principle of Counting
The number of...
Question
The number of ways to roll 5 six sided dice to get sum of 25 is________
126
Open in App
Solution
The correct option is
A
126
Number of possible values on top of dice:
=
x
+
x
2
+
x
3
+
x
4
+
x
5
+
x
6
=
x
(
1
−
x
6
)
1
−
x
W
e
n
e
e
d
t
o
f
i
n
d
c
o
e
f
f
i
c
i
e
n
t
o
f
x
25
:
(
x
(
1
−
x
6
)
1
−
x
)
5
=
x
5
(
1
−
x
6
)
5
.
1
(
1
−
x
)
5
=
x
25
⇒
C
o
e
f
f
i
c
i
e
n
t
o
f
x
20
i
n
(
1
−
x
6
)
5
⋅
1
(
1
−
x
)
5
⇒
C
o
e
f
f
i
c
i
e
n
t
o
f
x
20
i
n
(
1
−
5
x
6
+
10
x
12
−
10
x
18
+
5
x
24
−
x
30
)
(
ω
∑
n
=
0
[
n
+
4
4
]
x
n
)
⇒
C
o
e
f
f
i
c
i
e
n
t
o
f
x
20
i
n
{
(
20
+
4
C
4
)
−
5
×
(
14
−
4
C
4
)
+
10
×
(
8
−
4
C
4
)
−
10
×
(
2
−
4
C
4
)
]
x
20
⇒
=
(
24
C
4
)
−
5
×
(
18
C
4
)
+
10
×
(
12
C
4
)
−
10
×
(
6
C
4
)
=
10626
−
5
×
(
3060
)
+
10
×
(
495
)
−
10
×
(
15
)
= 126
Suggest Corrections
0
Similar questions
Q.
Find the number of ways in which we can get a sum less than or equal to 17 by throwing six distinct dices.
Q.
If
4
dice are rolled, then the number of ways of getting the sum
10
is
Q.
There are total
17
C
6
−
k
11
C
5
ways to get a sum of atmost
17
by throwing six distinct dice ,then
k
is equal to :
Q.
When a dice is rolled find the probability of getting a number less than or equal to 5
Q.
There are total
17
C
6
−
k
11
C
5
ways to get a sum of atmost
17
by throwing six distinct dice ,then
k
is equal to :
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Counting Principle
MATHEMATICS
Watch in App
Explore more
Fundamental Principle of Counting
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app