The number of zeroes coming immediately after the decimal point in the value of(0.2)25 is (Note: log102=0.30103)
A
16
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B
17
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C
18
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D
none of these
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Solution
The correct option is B17 Let, y=(0.2)25 Taking log both sides on base 10. ⇒log10y=25log100.2 ⇒log10y=25(log102−1) ⇒y=10−251025log102=10−251025(0.3013) ⇒y=10−17.4675 Ans: B