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Question

The number of zeros between the decimal point and first significant digit of (0.036)16 where log2=0.301 and log3=0.477

A
21
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B
22
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C
23
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D
24
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Solution

The correct option is C 23
y=(0.036)16
log(y)=16log(0.036)
log(y)=16log(361000)=16[log363log1010]
log(y)=16[log(22×32)3]=16[2(log2+log3)3]
log(y)=16[2(0.301+0.477)3]=23.104<23
So, that number has 23 zeros after this point.

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