The number of zeros coming immediately after the decimal point in the value of (0.2)25 is
(Given log102=0.3010)
A
16
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B
17
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C
18
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D
none of the above
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Solution
The correct option is B17 Let x=(0.2)25
Then log10x=25log100.2 ⇒log10x=25log10(210) ⇒log10x=25(log102−1) ⇒log10x=25×0.3010−25⇒log10x=7.525−25⇒log10x=−18+0.525
Hence, there are |−18+1|=17 zeros immediately after the decimal point.