Question

The number of zeros of the following quadratic polynomial are:
$4s^2-4s+1$.

Answer 1

Here we use factor formula:

Then $4s^2-4s+1=0$

$\Rightarrow 4s^2-2s-2s+1=0$

$\Rightarrow 2s(2s-1)-1(2s-1)=0$

$\Rightarrow (2s-1{)}^2=0$

So $s=\frac{1}{2},\frac{1}{2}$

$\therefore$ There will be two equal zeros $\frac{1}{2}$.