Question

The number $\sqrt{10}$ lies between $2$ integers $a$ and $b$ such that $b-a=1$. Then $b+a=?$

• A. $4$
• B. $5$
• C. $7$
• D. None of these

Answer 1

The correct option is C $7$

$1^2=1$

$2^2=4$

$3^2=9$

$4^2=16$

$\Rightarrow \sqrt{1}0$ lies between $3$ and $4$

$4=a,3=b$

$\therefore a+b=7$