The correct option is C Irrational number(√(2))^5=√(2)×√(2)×√(2)×√(2)×√(2)=4√(2) 4√(2) is irrational since it has a factor of √(2) which is non terminating and ...

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Standard IX

Mathematics

Irrational Numbers

The number √2...

Question

The number $(\sqrt{2})^{5}$ is

Rational number

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Natural number

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Irrational number

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None of these

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Solution

The correct option is C Irrational number
$(\sqrt{2})^{5} = \sqrt{2} \times \sqrt{2} \times \sqrt{2} \times \sqrt{2} \times \sqrt{2} = 4 \sqrt{2}$
$4 \sqrt{2}$ is irrational since it has a factor of $\sqrt{2}$ which is non-terminating and non-recurring.

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The number (√2)5 is

The correct option is C Irrational number(√2)5=√2×√2×√2×√2×√2=4√2 4√2 is irrational since it has a factor of √2 which is non-terminating and non-recurring.

The number $(\sqrt{2})^{5}$ is

The correct option is C Irrational number
$(\sqrt{2})^{5} = \sqrt{2} \times \sqrt{2} \times \sqrt{2} \times \sqrt{2} \times \sqrt{2} = 4 \sqrt{2}$
$4 \sqrt{2}$ is irrational since it has a factor of $\sqrt{2}$ which is non-terminating and non-recurring.