Question

The number that can be split like:
$(1\times 100)+(1\times 10)+(1\times 9)+(3\times {10}^{-1})+(6\times {10}^{-2})+(7\times {10}^{-3})$ is

• A. 1.19367
• B. 1193.67
• C. 11.9367
• D. 119.367

Answer 1

The correct option is D 119.367

Using standard form,
Number 119.367 can be split like:
$(1\times 100)+(1\times 10)+(1\times 9)+(3\times \frac{1}{10})+(6\times \frac{1}{100})+(7\times \frac{1}{1000})$

$\Rightarrow (1\times 100)+(1\times 10)+(1\times 9)+(3\times \frac{1}{{10}^1})+(6\times \frac{1}{{10}^2})+(7\times \frac{1}{{10}^3})$

$\Rightarrow (1\times 100)+(1\times 10)+(1\times 9)+(3\times {10}^{-1})+(6\times {10}^{-2})+(7\times {10}^{-3})$