The number ways in which $7$ players can throw a ball, so that the youngest player may not be the last?

4000

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4320

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2160

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5300

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Solution

The correct option is B $4320$
Total number of players $= 7$
He/She has $^{6} C_{1}$ Chance for his placement
Remaining $6$ players can have chance in $6!$ Ways
Therefore total possiblities
$= 6 \times 720 = 4320$

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The number of ways of arranging 6 players to throw the hand ball so that the oldest player may not throw first is

6

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