The number with four or more digits is exactly divisible by $8,$ if the number formed by its last two digits ( i.e, ones and tens ) is exactly divisible by $8 .$

True

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False

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Solution

The correct option is B False
According to the divisibility test of $8$ : A number with 4 or more digits is divisible by $8$ , if the number formed by the last three digits is divisible by $8 .$
For example: $1888$ is divisible by $8$ since the last three digits of $1888$ which are $888$ are divisible by $8 .$
Hence , the number with four or more digits is exactly divisible by $8,$ if the number formed by its last two digits ( i.e, ones and tens ) is not exactly divisible by $8 .$

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The number with four or more digits is exactly divisible by 8, if the number formed by its last two digits ( i.e, ones and tens ) is exactly divisible by 8.

The number with four or more digits is exactly divisible by $8,$ if the number formed by its last two digits ( i.e, ones and tens ) is exactly divisible by $8 .$