The number x-1-242424- can be expressed in the form x-pq- where p and q are positive integers having no common factors- Then p-q equals -

The correct option is D 74 Given, x=1.24242 #160; #160; .....(1) 100 x=124.2424 #160; #160; ....(2)Substract eqn (1) from eqn (2), we ...

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Standard XII

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Question

The number $x = 1.242424....$ can be expressed in the form $x = \frac{p}{q}$ , where $p$ and $q$ are positive integers having no common factors. Then $p + q$ equals ____.

72

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74

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41

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53

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Solution

The correct option is D $74$
Given, $x = 1.24242$ .....(1)
$100 x = 124.2424$ ....(2)
Substract eqn (1) from eqn (2), we get
$99 x = 123 x = \frac{123}{99} = \frac{41}{33}$
Here $p = 41$ and $q = 33$
Thus $p + q = 41 + 33 = 74$

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The number x=1.242424.... can be expressed in the form x=pq, where p and q are positive integers having no common factors. Then p+q equals ____.

The correct option is D 74Given, x=1.24242 .....(1)100x=124.2424 ....(2)Substract eqn (1) from eqn (2), we get99x=123x=12399=4133Here p=41 and q=33Thus p+q=41+33=74

The number $x = 1.242424....$ can be expressed in the form $x = \frac{p}{q}$ , where $p$ and $q$ are positive integers having no common factors. Then $p + q$ equals ____.

The correct option is D $74$
Given, $x = 1.24242$ .....(1)
$100 x = 124.2424$ ....(2)
Substract eqn (1) from eqn (2), we get
$99 x = 123 x = \frac{123}{99} = \frac{41}{33}$
Here $p = 41$ and $q = 33$
Thus $p + q = 41 + 33 = 74$