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Standard XII

Mathematics

Permutation under Restriction

The numbers 1...

Question

The numbers $1, 2, 3$ and $4$ are written separately on four slips of paper. The slips are put in a box and mixed thoroughly, A person draws two slips from the box, one after the other, without replacement. The total number of possible outcomes for the experiment is

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Solution

From the question it is given that, $1, 2, 3, 4$ are the numbers written on the four slip. When two slips are drawn without replacement the first event has $4$ possible outcomes and the second event has $3$ possible outcomes because $1$ slip is already picked.
Therefore, the total number of possible outcomes $= (4 \times 3) = 12$

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Permutation under Restriction

Standard XII Mathematics

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The numbers 1,2,3 and 4 are written separately on four slips of paper. The slips are put in a box and mixed thoroughly, A person draws two slips from the box, one after the other, without replacement. The total number of possible outcomes for the experiment is

The numbers $1, 2, 3$ and $4$ are written separately on four slips of paper. The slips are put in a box and mixed thoroughly, A person draws two slips from the box, one after the other, without replacement. The total number of possible outcomes for the experiment is