Question

The numbers $1$ to $10$ are each printed on a counter and the $10$ counters are placed in a bag. If one counter is picked at random, what is the probability that the number on it is a multiple of $3$?

Answer 1

Step 1 Finding the favorable and total outcomes:

There are $10$ counters placed in a bag, so the total outcome is $10$.

In the range $1$ to $10$ the numbers which are multiples of $3$ are,

$3,6,9$

So the favourable outcomes are $3$.

Step 2 Finding the probability that the drawn counter has a multiple of $3$ on it:

The formula for the probability is expressed as,

$Probability=\frac{Number of favorable outcomes}{Total number of outcomes}$

Substitute favorable number of outcomes as $3$ and the total number of outcomes as $10$.

$\therefore P\left(multipleof3\right)=\frac{3}{10}$

Hence, the probability of a counter which is multiple of $3$ from a bag of $10$ counters numbered $1$ to $10$ is $\frac{3}{10}$.