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Insertion of AM's Between 2 Numbers

The numbers ...

Question

The numbers $4, 6 a n d 8$ are the frequencies of $(x + 2), x a n d (x - 1)$ respectively . If their arithmetic mean is $8,$ the value of $x$ is

5

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6

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7

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8

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Solution

The correct option is C $8$
$8 =$ $\frac{4 \times (x + 2) + 6 x + 8 \times (x - 1)}{4 + 6 + 8}$
$= \frac{4 x + 8 + 6 x + 8 x - 8}{18}$
$∴$ $x = 8$

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