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Question

The numbers of integral of 'a' for which the equation is satisfied
4sin(X+3π3)cos(X3π6)=a2+3sin2Xcos2X

A
2
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B
3
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C
4
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D
5
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Solution

The correct option is D 5
2(sin(2x+π6)+sinπ2)=a2+3sin2xcos2x
2(sin2x32+cos2x12+1)=a2+3sin2xcos2x
2cos 2x +2 = a2 - cos 2x
2cos 2x = a2 - 2
2a222
Oa24aϵ[2,2]


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