The numbers of points of intersection of $2 y = 1$ and $y = sin x$ , in $- 2 π \leq x \leq 2 π$ is

1

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2

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3

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4

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Solution

The correct option is D $4$
Given $y = \frac{1}{2}, y = s i n x$

$\Rightarrow s i n x = \frac{1}{2}$

But $- 2 π \leq x \leq 2 π$ (Given)

Hence, $x = \frac{π}{6}, \frac{5 π}{6}, \frac{- 7 π}{6}, \frac{- 11 π}{6}$

Therefore, number of solutions $= 4$

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