Question

The numerator of a fraction is 3 less than its denominator. If 1 is added to the denominator, the fraction is decreased by 1/15. Find the fraction.

Answer 1

Let the numerator be x and denominator be y,

then fraction will be x/y

x= y-3 ............(1)

ALSO

x/y+1 = x/y-1/15

putting x= y-3 from (1)

y-3/y+1=y-3/y-1/15

$15y^2-45y=14y^2-45y+14y-45$

$y^2-14y+45=0$

$(y-9)(y-5)=0$

$y=9,y=5$

when we solve the ans. coming will be y = 9 and y = 5

putting values of y in (1)

fraction is

6/9 and2/5