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Real Gases

The numerical...

Question

The numerical value of ' $a$ ' the van der Waals' constant is maximum for:

H e

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H_{2}

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O_{2}

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N H_{3}

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Solution

The correct option is D $N H_{3}$
The ease of liquification of a gas depends on their intermolecular force of attraction which in turn is measured in terms of van der Waals’ constant ‘ $a$ ’.
Hence, higher the value of ‘ $a$ ’, greater the intermolecular force of attraction, easier the liquification. In the present case, $N H_{3}$ has highest ‘ $a$ ’, can most easily be liquefied.
Hence option $D$ is correct answer.

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